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The average (arithmetic mean) of the two numbers 3x and 3y i
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25 Nov 2019, 08:08
25 Nov 2019, 08:08
1
Expert Reply
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Question Stats:
86% (00:39) correct
13% (00:13) wrong based on 66 sessions
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The average (arithmetic mean) of the two numbers 3x and 3y is 48.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The average (arithmetic mean) of the two numbers 2x and 2y |
30 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: The average (arithmetic mean) of the two numbers 3x and 3y i
[#permalink]
28 Nov 2019, 11:05
28 Nov 2019, 11:05
1
The answer is A
(3x + 3y)/2 =48
=>3x+3y = 96
=>x+y =32
A = (2x +2y )/2
= 2(x+y)/2
=x+y
=32
So A is bigger
(3x + 3y)/2 =48
=>3x+3y = 96
=>x+y =32
A = (2x +2y )/2
= 2(x+y)/2
=x+y
=32
So A is bigger
Re: The average (arithmetic mean) of the two numbers 3x and 3y i
[#permalink]
06 Apr 2020, 13:45
06 Apr 2020, 13:45
AAAAA
