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To serve as team coach, 1 person is to be selected from amon
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20 May 2020, 09:04
20 May 2020, 09:04
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34% (01:41) correct
65% (02:03) wrong based on 147 sessions
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To serve as team coach, 1 person is to be selected from among the people in Set A. The 9 team players are to be selected from among the people in Set B, which has at least that many people. There are 5 times as many different teams possible as there are different coaches possible.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of people in Set A |
The number of people in Set B |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: To serve as team coach, 1 person is to be selected from amon
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20 May 2020, 09:05
20 May 2020, 09:05
Expert Reply
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Re: To serve as team coach, 1 person is to be selected from amon
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02 Jun 2020, 21:16
02 Jun 2020, 21:16
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This can be solved by assuming some numbers (satisfying the given criteria) for the teams.
Case 1: A < B
Number of members in Team A = 2
Number of members in Team B = 10
Number of ways a coach can be selected = 2c1 = 2 (10/5)
Number of ways a team of 9 people can be selected = 10c9 = 10
Case 2: A = B
Number of members in Team A = 11
Number of members in Team B = 11
Number of ways a coach can be selected = 11c1 = 11 (55/5)
Number of ways a team of 9 people can be selected = 11c9 = 55
Case 3: A > B
Number of members in Team A = 44
Number of members in Team B = 12
Number of ways a coach can be selected = 44c1 = 44 (220/5)
Number of ways a team of 9 people can be selected = 12c9 = 220
Therefore, answer is D
Case 1: A < B
Number of members in Team A = 2
Number of members in Team B = 10
Number of ways a coach can be selected = 2c1 = 2 (10/5)
Number of ways a team of 9 people can be selected = 10c9 = 10
Case 2: A = B
Number of members in Team A = 11
Number of members in Team B = 11
Number of ways a coach can be selected = 11c1 = 11 (55/5)
Number of ways a team of 9 people can be selected = 11c9 = 55
Case 3: A > B
Number of members in Team A = 44
Number of members in Team B = 12
Number of ways a coach can be selected = 44c1 = 44 (220/5)
Number of ways a team of 9 people can be selected = 12c9 = 220
Therefore, answer is D
