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Re: f, g, and h are consecutive prime numbers such that f < g [#permalink]
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sandy wrote:
f, g, and h are consecutive prime numbers such that f < g < h.

Quantity A
Quantity B
f + g + h
3g


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Drill 2
Question: 6
Page: 287


----PLUG IN VALUES--------
Take 2,3,5
3 times 3 < 2 + 3 + 5

Take 3,5,7
3 times 5 = 3 + 5 + 7

Thus contradicting statemements gives us D answer
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Re: f, g, and h are consecutive prime numbers such that f < g [#permalink]
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Re: f, g, and h are consecutive prime numbers such that f < g [#permalink]
To equal a and b.

f + g + h = 3g

The difference between f, g and h, have to be equal to 'g'. So, there must be an arithmetic succession (pattern) to obtain this. This occurs in the case os 3,5,7 (prime numbers with an arithmetic succession) but we need that in general prime numbers don't have a pattern. In conclusion, we have a case that meets a = b, but in other cases we need that a will be different than b. So the answer is D.
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Re: f, g, and h are consecutive prime numbers such that f < g [#permalink]
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Re: f, g, and h are consecutive prime numbers such that f < g [#permalink]
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