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Sum of the angles (in degrees) in a pentagon
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24 Sep 2018, 11:52
24 Sep 2018, 11:52
1
Expert Reply
00:00
Question Stats:
90% (00:15) correct
9% (00:19) wrong based on 98 sessions
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Quantity A |
Quantity B |
Sum of the angles (in degrees) in a pentagon |
500° |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: Sum of the angles (in degrees) in a pentagon
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24 Sep 2018, 13:13
24 Sep 2018, 13:13
3
Carcass wrote:
Quantity A |
Quantity B |
Sum of the angles (in degrees) in a pentagon |
500° |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Useful rule: the sum of the angles in an n-sided polygon = (n - 2)(180°)
A pentagon has 5 sides
So, the sum of the angles = (5 - 2)(180°)
= (3)(180°)
= 540°
We get:
Quantity A: 540°
Quantity B: 500°
Answer: A
Cheers,
Brent
Re: Sum of the angles (in degrees) in a pentagon
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18 Jan 2019, 06:41
18 Jan 2019, 06:41
(5 - 2)(180°)
= (3)(180°)
= 540°
= (3)(180°)
= 540°
