Last visit was: 25 Nov 2024, 04:27 It is currently 25 Nov 2024, 04:27

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4813
Own Kudos [?]: 11197 [8]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12197 [0]
Given Kudos: 136
Send PM
avatar
Intern
Intern
Joined: 04 Aug 2019
Posts: 16
Own Kudos [?]: 6 [0]
Given Kudos: 0
Send PM
Moderator
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1111
Own Kudos [?]: 965 [1]
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Send PM
Re: GRE Math Challenge #104- x > 0 [#permalink]
1
Bookmarks
We need to compare \(\frac{(590+x)}{800}\) and \(\frac{(600+x)}{790}\)
and we know that x > 0

Now, lets look at the numerator of both the quantities

Numerator for Quantity A (590+x) < Numerator for Quantity B (600+x)

Now, lets look at the denominator of both the quantities

Denominator for Quantity A (800) > Denominator for Quantity B (790)

Since Numerator of Quantity A < Numerator of Quantity B and Denominator for Quantity A > Denominator for Quantity B
[numerical example 12/20 < 13/19]

So, Quantity A < Quantity B

So, Answer will be B
Hope it helps!
Moderator
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1111
Own Kudos [?]: 965 [1]
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Send PM
GRE Math Challenge #104- x > 0 [#permalink]
1
JNeen

Just adding few things in your solution
When you are dividing both numerator and denominator by 10 then even x will become \(\frac{x}{10}\)

Now, x/10 can be assumed as X, lets continue with the solution and we know that X will also be > 0

Now, We know that 59/80 < 60/79 so Quantity A < Quantity B
So we can ignore X/80 and X/79 as in any case X/80 < X/79 and it will add to Quantity A < Quantity B
So, your approach was more or less correct with these minor additions.
Good work!
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5053
Own Kudos [?]: 75 [0]
Given Kudos: 0
Send PM
Re: GRE Math Challenge #104- x > 0 [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: GRE Math Challenge #104- x > 0 [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne