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(x+y)^2
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31 Dec 2020, 01:01
31 Dec 2020, 01:01
Expert Reply
00:00
Question Stats:
66% (01:02) correct
33% (00:41) wrong based on 24 sessions
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Attachment:
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Quantity A |
Quantity B |
\((x+y)^2\) |
\(a^2+b^2+c^2+d^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: (x+y)^2
[#permalink]
31 Dec 2020, 01:46
31 Dec 2020, 01:46
1
Qt A
\((x+y)^2\)
The triangle is a right angle so we can apply the Pythagoras Theorem.
\((x+y)^2\) = \((a+b)^2\) + \((c+d)^2\) = \((a)^2\) + 2ab + \((b)^2\) + \((c)^2\) + 2cd + \((d)^2\)
= \(a^2+b^2+c^2+d^2\) + 2 ( ab + cd )
Qt B
\(a^2+b^2+c^2+d^2\)
As a , b , c , d are sides of a triangle, they will be positive so Qt A is greater than Qt B
Answer A
\((x+y)^2\)
The triangle is a right angle so we can apply the Pythagoras Theorem.
\((x+y)^2\) = \((a+b)^2\) + \((c+d)^2\) = \((a)^2\) + 2ab + \((b)^2\) + \((c)^2\) + 2cd + \((d)^2\)
= \(a^2+b^2+c^2+d^2\) + 2 ( ab + cd )
Qt B
\(a^2+b^2+c^2+d^2\)
As a , b , c , d are sides of a triangle, they will be positive so Qt A is greater than Qt B
Answer A
gmatclubot
Re: (x+y)^2 [#permalink]
31 Dec 2020, 01:46
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