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Re: June can run 6 laps in x minutes. Miriam can run 11 [#permalink]
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This a pretty easy question.

Say J run 6 laps in x minutes and we assume will x be 1 x=1

So M will run 11 laps in 2x so in 2 minutes

A) Jane 6 laps = 1 minute so 24 laps will be = x

Solve for x = 4

B ) M 11 laps in 2 minutes so 22 laps in 4 minutes. The double.

Answer is C
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Re: June can run 6 laps in x minutes. Miriam can run 11 [#permalink]
Carcass wrote:
This a pretty easy question.

Say J run 6 laps in x minutes and we assume will x be 1 x=1

So M will run 11 laps in 2x so in 2 minutes

A) Jane 6 laps = 1 minute so 24 laps will be = x

Solve for x = 4

B ) M 11 laps in 2 minutes so 22 laps in 4 minutes. The double.

Answer is C



Thanks for the solution Carcass! I got my formula wrong in the rush...
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Re: June can run 6 laps in x minutes. Miriam can run 11 [#permalink]
I´ve a question in this one..

If we use the calculator then for Jane are 240 mins and for M are 239.8 min.

Why should we round to the next integer if its not stated in the question?

Regards!
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Re: June can run 6 laps in x minutes. Miriam can run 11 [#permalink]
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FCOCGALVAN wrote:
I´ve a question in this one..

If we use the calculator then for Jane are 240 mins and for M are 239.8 min.

Why should we round to the next integer if its not stated in the question?

Regards!


No but from the question is implied that those are whole numbers.

However, rounded or not, the answer is still the same

I would focus more on solving it rather on these nuances

Regards
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Re: June can run 6 laps in x minutes. Miriam can run 11 [#permalink]
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