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ABC and DEF are right triangles. Each side of ∆ABC is twice
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24 Apr 2018, 09:28
24 Apr 2018, 09:28
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Question Stats:
71% (00:55) correct
28% (00:46) wrong based on 42 sessions
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ABC and DEF are right triangles. Each side of ∆ABC is twice the length of the corresponding side of ∆DEF.
Quantity A |
Quantity B |
The area of ∆DEF/The area of ∆ABC |
\(\frac{1}{2}\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for the right answer and solution.
Re: ABC and DEF are right triangles. Each side of ∆ABC is twice
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04 May 2018, 04:07
04 May 2018, 04:07
1
Area of triangle is 1/2*base*height
For right angle triangle, base and height form 2 sides of the triangle.
As the values of both of them are double, 1/2*b*h would become 1/2*2b*2h =4*1/2*b*h
So B which is 1/2 is greater than A which is 1/4
For right angle triangle, base and height form 2 sides of the triangle.
As the values of both of them are double, 1/2*b*h would become 1/2*2b*2h =4*1/2*b*h
So B which is 1/2 is greater than A which is 1/4
gmatclubot
Re: ABC and DEF are right triangles. Each side of ∆ABC is twice [#permalink]
04 May 2018, 04:07
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