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The least common multiple of 6 and 10
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31 Dec 2021, 07:15
31 Dec 2021, 07:15
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Question Stats:
81% (01:00) correct
18% (01:26) wrong based on 22 sessions
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Quantity A |
Quantity B |
The least common multiple of 6 and 10 |
The greatest common divisor of 80 and 140 |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
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Re: The least common multiple of 6 and 10
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31 Dec 2021, 07:40
31 Dec 2021, 07:40
1
Carcass wrote:
Quantity A |
Quantity B |
The least common multiple of 6 and 10 |
The greatest common divisor of 80 and 140 |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
The least common multiple of 6 and 10 is 30
The greatest common divisor of 80 and 140 is 20
So we have:
QUANTITY A: 30
QUANTITY B: 20
Answer: A
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GMAT 1: 700 Q51 V31
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The least common multiple of 6 and 10
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27 Oct 2022, 10:31
27 Oct 2022, 10:31
1
Quantity A: The least common multiple of 6 and 10
6 = 2*3 = \(2^1 * 3^1\)
10 = 2*5 = \(2^1 * 5^1\)
To find the LCM take all the terms and take their highest power in all of the above.
=> LCM(6,10) = \(2^1 * 3^1 * 5^1\) = 30
Quantity B: The greatest common divisor of 80 and 140
80 = 16*5 = \(2^4 * 5^1\)
140 = 4 * 5 * 7 = \(2^2 * 5^1 * 7^1\)
To find the GCD take all the common terms and take their lowest power in all of the above.
=> GCD(80,140) = \(2^2 * 5^1\) = 20
Clearly, Quantity A(30) > Quantity B(20)
So, Answer will be A
Hope it helps!
To learn more about LCM and GCD watch the following videos
6 = 2*3 = \(2^1 * 3^1\)
10 = 2*5 = \(2^1 * 5^1\)
To find the LCM take all the terms and take their highest power in all of the above.
=> LCM(6,10) = \(2^1 * 3^1 * 5^1\) = 30
Quantity B: The greatest common divisor of 80 and 140
80 = 16*5 = \(2^4 * 5^1\)
140 = 4 * 5 * 7 = \(2^2 * 5^1 * 7^1\)
To find the GCD take all the common terms and take their lowest power in all of the above.
=> GCD(80,140) = \(2^2 * 5^1\) = 20
Clearly, Quantity A(30) > Quantity B(20)
So, Answer will be A
Hope it helps!
To learn more about LCM and GCD watch the following videos
