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sqrt8+sqrt13
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26 Mar 2021, 08:05
26 Mar 2021, 08:05
Expert Reply
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Question Stats:
99% (00:43) correct
0% (00:00) wrong based on 14 sessions
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Quantity A |
Quantity B |
\(\sqrt{8}\)+\(\sqrt{13} \) |
\(\sqrt{19}+\sqrt{9}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: sqrt8+sqrt13
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26 Mar 2021, 08:29
26 Mar 2021, 08:29
Carcass wrote:
Quantity A |
Quantity B |
\(\sqrt{8}\)+\(\sqrt{13} \) |
\(\sqrt{19}+\sqrt{9}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(\sqrt{8}\) < \(\sqrt{9}\)
\(\sqrt{13}\) < \(\sqrt{19}\)
Adding both the inequalities;
\(\sqrt{8}\)+\(\sqrt{13}\) < \(\sqrt{9}\)+\(\sqrt{19} \)
Hence, option B
Re: sqrt8+sqrt13
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26 Mar 2021, 14:08
26 Mar 2021, 14:08
Quantity A: <3 + <4
Quantity B: <5 + 3
Quantity B is clearly greater
Quantity B: <5 + 3
Quantity B is clearly greater
