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a>1 and a-1=b
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20 Apr 2021, 23:40
20 Apr 2021, 23:40
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\(a>1\) and \(a-1=b\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
\(b^2\) |
\(a^2-1\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: a>1 and a-1=b
[#permalink]
21 Apr 2021, 11:12
21 Apr 2021, 11:12
2
Carcass wrote:
\(a>1\) and \(a-1=b\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(b^2\) |
\(a^2-1\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Col. A: \(b^2\)
Col. B: \((b + 1)^2 - 1\)
Col. A: \(b^2\)
Col. B: \(b^2 + 1 + 2b - 1\)
Subtracting \(b^2\) from both sides;
Col. A: \(0\)
Col. B: \(2b\)
Since, \(a > 1\) and \(a - 1 = b\), b has to be a positive number
Hence, option B
Another way could be to assume some values
gmatclubot
Re: a>1 and a-1=b [#permalink]
21 Apr 2021, 11:12
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