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Joined: 16 Apr 2020
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WE:Education (Education)
n is a positive integer, A = 3n and B = n/3
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02 Aug 2021, 22:06
02 Aug 2021, 22:06
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Question Stats:
51% (02:14) correct
48% (02:05) wrong based on 58 sessions
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\(n\) is a positive integer
A = \(3n\)
B = \(\frac{n}{3}\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
A = \(3n\)
B = \(\frac{n}{3}\)
Quantity A |
Quantity B |
Number of values of \(n\) for which A and B are 3-digit integers? |
15 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
n is a positive integer, A = 3n and B = n/3
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03 Aug 2021, 20:07
03 Aug 2021, 20:07
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Explanation:
A is a 3 digit integer
i.e. \(100 ≤ 3n ≤ 999\)
\(33.33 ≤ n ≤ 333\)
B is a 3 digit integer
i.e. \(100 ≤ \frac{n}{3} ≤ 999\)
\(300 ≤ n ≤ 2997\)
This means \(300 ≤ n ≤ 333\)
Number of value of \(n\) which are multiples of 3= \(\frac{333 - 300}{3} + 1= 12\)
Col. A: 12
Col. B: 15
Hence, option B
A is a 3 digit integer
i.e. \(100 ≤ 3n ≤ 999\)
\(33.33 ≤ n ≤ 333\)
B is a 3 digit integer
i.e. \(100 ≤ \frac{n}{3} ≤ 999\)
\(300 ≤ n ≤ 2997\)
This means \(300 ≤ n ≤ 333\)
Number of value of \(n\) which are multiples of 3= \(\frac{333 - 300}{3} + 1= 12\)
Col. A: 12
Col. B: 15
Hence, option B
General Discussion
Re: n is a positive integer, A = 3n and B = n/3
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15 Oct 2023, 06:45
15 Oct 2023, 06:45
KarunMendiratta wrote:
Explanation:
A is a 3 digit integer
i.e. \(100 ≤ 3n ≤ 999\)
\(33.33 ≤ n ≤ 333\)
B is a 3 digit integer
i.e. \(100 ≤ \frac{n}{3} ≤ 999\)
\(300 ≤ n ≤ 2997\)
This means \(300 ≤ n ≤ 333\)
Number of value of \(n\) which are multiples of 3= \(\frac{333 - 300}{3} + 1= 12\)
Col. A: 12
Col. B: 15
Hence, option B
A is a 3 digit integer
i.e. \(100 ≤ 3n ≤ 999\)
\(33.33 ≤ n ≤ 333\)
B is a 3 digit integer
i.e. \(100 ≤ \frac{n}{3} ≤ 999\)
\(300 ≤ n ≤ 2997\)
This means \(300 ≤ n ≤ 333\)
Number of value of \(n\) which are multiples of 3= \(\frac{333 - 300}{3} + 1= 12\)
Col. A: 12
Col. B: 15
Hence, option B
Sir, in the last step-- why are we dividing by 3? The question simply asks the # of 3-digit numbers
