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x y = 1, x > 0 and y > 0
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10 Sep 2024, 02:47
10 Sep 2024, 02:47
Expert Reply
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Question Stats:
100% (00:39) correct
0% (00:00) wrong based on 5 sessions
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x – y = 1, x > 0 and y > 0
Quantity A |
Quantity B |
\(x^2-y^2 \) |
0 |
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Re: x y = 1, x > 0 and y > 0
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20 Sep 2024, 02:29
20 Sep 2024, 02:29
A = x^2 - y^2 = (x - y)(x + y) = x + y > 0 because x > 0, y > 0
=> A
=> A
x y = 1, x > 0 and y > 0
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26 Oct 2024, 05:39
26 Oct 2024, 05:39
1
x^2 - y^2 = (x+y) (x-y) = (x+y)(1)
Since x>0, y>0:
x+y>0
x-y=1>0
=> x^2 - y^2 > 0
Since x>0, y>0:
x+y>0
x-y=1>0
=> x^2 - y^2 > 0
