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A(2,3), B(5,7), C(–2, 5), and D(1,1) D are points in a coordinate plan
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01 Sep 2021, 10:10
01 Sep 2021, 10:10
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A(2,3), B(5,7), C(–2, 5), and D(1,1) D are points in a coordinate plane.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The distance between A and B |
The distance between C and D |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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A(2,3), B(5,7), C(–2, 5), and D(1,1) D are points in a coordinate plan
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02 Sep 2021, 06:23
02 Sep 2021, 06:23
1
Carcass wrote:
A(2,3), B(5,7), C(–2, 5), and D(1,1) D are points in a coordinate plane.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The distance between A and B |
The distance between C and D |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Distance between \((x_1, y_1)\) and \((x_2, y_2)\) \(= \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}\)
QUANTITY A: The distance between A(2,3) and B(5,7)
Distance \(= \sqrt{(5 -2)^2 + (7 -3)^2}\)
\(= \sqrt{3^2 + 4^2}\)
\(= \sqrt{25}\)
\(= 5\)
QUANTITY B: The distance between C(–2, 5), and D(1,1)
Distance \(= \sqrt{(1 -(-2))^2 + (1 -5)^2}\)
\(= \sqrt{3^2 + (-4)^2}\)
\(= \sqrt{25}\)
\(= 5\)
Answer: C
gmatclubot
A(2,3), B(5,7), C(–2, 5), and D(1,1) D are points in a coordinate plan [#permalink]
02 Sep 2021, 06:23
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