We have $\(\mathrm{A}=125 \times 165 \times 688 \& \mathrm{~B}=178 \times 14312 \times 76768\)$; we need to compare the units' digit of number A with the units' digit of number B .

The units' digit of any product is obtained by taking the units digit of all numbers which are being multiplied.

So, finding the units digit of $\(\mathrm{A}=125 \times 165 \times 688\)$ is same as finding the units' digit of the product $\(5 \times 5 \times 8\)$ which is zero.

Similarly finding the units digit of $\(B=178 \times 14312 \times 76768\)$ is same as finding the units' digit of the product $\(8 \times 2 \times 8\)$ which is equal to $\(6 \times 8=8\)$ only.

Hence column B has higher quantity, so the answer is (B).