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(x+y)(x-y) or x^+y^2
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05 Jan 2022, 06:16
05 Jan 2022, 06:16
Expert Reply
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Question Stats:
46% (00:25) correct
53% (00:26) wrong based on 15 sessions
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Quantity A |
Quantity B |
\([x+y][x-y]\) |
\(x^2+y^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
See more on this topic Equations
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Joined: 10 Apr 2015
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Re: (x+y)(x-y) or x^+y^2
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05 Jan 2022, 06:38
05 Jan 2022, 06:38
Carcass wrote:
Quantity A |
Quantity B |
\([x+y][x-y]\) |
\(x^2+y^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
See more on this topic Equations
We can solve this question using matching operations (my favorite Quantitative Comparison strategy)
Given:
Quantity A: \((x+y)(x-y)\)
Quantity B: \(x^2+y^2\)
Expand and simplify Quantity A to get:
Quantity A: \(x^2-y^2\)
Quantity B: \(x^2+y^2\)
Subtract \(x^2\) from both quantities:
Quantity A: \(-y^2\)
Quantity B: \(y^2\)
Add \(y^2\) to both quantities:
Quantity A: \(0\)
Quantity B: \(2y^2\)
If \(y = 0\), then the two quantities are equal
If \(y = 1\), then the two quantities are NOT equal
Answer: D
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gmatclubot
Re: (x+y)(x-y) or x^+y^2 [#permalink]
05 Jan 2022, 06:38
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