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Re: x + y < z [#permalink]
Expert Reply
GreenlightTestPrep wrote:
Carcass wrote:
\(x + y < z\)

Quantity A
Quantity B
\(2x-z\)
\(-y\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Given:
Quantity A: 2x - z
Quantity B: -y

Let's try to make the quantities RESEMBLE the given inequality: x + y < z

Add y both quantities to get:
Quantity A: 2x - z + y
Quantity B: 0

Add z both quantities to get:
Quantity A: 2x + y
Quantity B: z

SO CLOSE!!
If Quantity A were x + y (rather than 2x + y), we'd be able to conclude that Quantity B is bigger (since we know that x + y < z)
HOWEVER, this is not the case.

Given all of this, it seems likely that the correct answer might be D.

So, let's test some possible values of x, y and z (that satisfies the restriction that x + y < z)

case i: x = 3, y = 1 and z = 5 (this satisfies the inequality x + y < z)
We get:
Quantity A: 2x + y = 2(3) + 1 = 7
Quantity B: z = 5
In this case, Quantity A is greater

case ii: x = 3, y = 1 and z = 500 (this satisfies the inequality x + y < z)
We get:
Quantity A: 2x + y = 2(3) + 1 = 7
Quantity B: z = 500
In this case, Quantity B is greater

Answer: D

Cheers,
Brent



Stellar explanation :)
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Re: x + y < z [#permalink]
Carcass wrote:
GreenlightTestPrep wrote:
Carcass wrote:
\(x + y < z\)

Quantity A
Quantity B
\(2x-z\)
\(-y\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Given:
Quantity A: 2x - z
Quantity B: -y

Let's try to make the quantities RESEMBLE the given inequality: x + y < z

Add y both quantities to get:
Quantity A: 2x - z + y
Quantity B: 0

Add z both quantities to get:
Quantity A: 2x + y
Quantity B: z

SO CLOSE!!
If Quantity A were x + y (rather than 2x + y), we'd be able to conclude that Quantity B is bigger (since we know that x + y < z)
HOWEVER, this is not the case.

Given all of this, it seems likely that the correct answer might be D.

So, let's test some possible values of x, y and z (that satisfies the restriction that x + y < z)

case i: x = 3, y = 1 and z = 5 (this satisfies the inequality x + y < z)
We get:
Quantity A: 2x + y = 2(3) + 1 = 7
Quantity B: z = 5
In this case, Quantity A is greater

case ii: x = 3, y = 1 and z = 500 (this satisfies the inequality x + y < z)
We get:
Quantity A: 2x + y = 2(3) + 1 = 7
Quantity B: z = 500
In this case, Quantity B is greater


:lol: :lol: :lol:

Answer: D

Cheers,
Brent



Stellar explanation :)
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Re: x + y < z [#permalink]
1
Well, you know that x + y < z

A: 2x-z
--------------------
B: -y

Well,

x+y < z
x - z < -y

Now, you compare "2x - z" and "x - z". Indeed, you have to compare only "2x" and "x". Since you don´t know if x is positive or negative, the answer is D
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Re: x + y < z [#permalink]
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