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n+7/3+n-3/4 or 7n+19/7
[#permalink]
16 Jun 2022, 03:17
16 Jun 2022, 03:17
Expert Reply
00:00
Question Stats:
76% (01:25) correct
23% (00:52) wrong based on 13 sessions
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\(n>1\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(\frac{n+7}{3}+\frac{n-3}{4}\) |
\(\frac{7n+19}{7} \) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: n+7/3+n-3/4 or 7n+19/7
[#permalink]
16 Jun 2022, 03:37
16 Jun 2022, 03:37
1
Quantity A is equivalent to:
\(\frac{7n+19}{12}\)
Numerator is the same, denominator is different
The larger the denominator, the smaller the value
Answer is (B)
\(\frac{7n+19}{12}\)
Numerator is the same, denominator is different
The larger the denominator, the smaller the value
Answer is (B)
gmatclubot
Re: n+7/3+n-3/4 or 7n+19/7 [#permalink]
16 Jun 2022, 03:37
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