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Number of different triangles possible using the given points
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31 Oct 2022, 03:16
31 Oct 2022, 03:16
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Question Stats:
59% (00:50) correct
40% (00:52) wrong based on 22 sessions
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Quantity A |
Quantity B |
Number of different triangles possible using the given points as vertices |
42 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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GRE Math Essentials (2022)
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GRE - Math Book
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Re: Number of different triangles possible using the given points
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15 Nov 2022, 14:58
15 Nov 2022, 14:58
Expert Reply
The brute force approach is to count all the triangles literally inside the circle you can draw
Just take one point as a reference and then join with another two points. Then the point after until you map the entire circle.
It will not take that much time but is tedious. It is not the way the question is conceived to be solved.
Instead, this is a combinatorics question in disguise
You have seven points and three sides for each triangle
\(\frac{7!}{3!4!}= \frac{7*6*5*4*3*2*1}{3*2*1-4*3*2*1}=35\)
B is the answer
Just take one point as a reference and then join with another two points. Then the point after until you map the entire circle.
It will not take that much time but is tedious. It is not the way the question is conceived to be solved.
Instead, this is a combinatorics question in disguise
You have seven points and three sides for each triangle
\(\frac{7!}{3!4!}= \frac{7*6*5*4*3*2*1}{3*2*1-4*3*2*1}=35\)
B is the answer
gmatclubot
Re: Number of different triangles possible using the given points [#permalink]
15 Nov 2022, 14:58
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