GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
a ≠ –b
[#permalink]
15 Apr 2018, 04:34
15 Apr 2018, 04:34
Expert Reply
00:00
Question Stats:
80% (00:46) correct
19% (01:14) wrong based on 46 sessions
Hide Show timer Statistics
a ≠ –b
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{6a^2+12ab+6b^2}{(a+b)}\) |
\(6(a+b)\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 5
Page: 511
Question: 5
Page: 511
Re: a ≠ –b
[#permalink]
18 Apr 2018, 15:44
18 Apr 2018, 15:44
Expert Reply
Explanation
Whenever you see exponents, think common quadratics.
If you factor the 6 out of the numerator in Quantity A, you get \(6(a^2 + 2ab + b^2)\), which includes a common quadratic \((a +b)^2\).
Then you can cancel (a + b) from both the numerator and the denominator; Quantity A is really just 6(a + b). The quantities are equal.
Whenever you see exponents, think common quadratics.
If you factor the 6 out of the numerator in Quantity A, you get \(6(a^2 + 2ab + b^2)\), which includes a common quadratic \((a +b)^2\).
Then you can cancel (a + b) from both the numerator and the denominator; Quantity A is really just 6(a + b). The quantities are equal.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: a ≠ –b
[#permalink]
06 Sep 2021, 10:16
06 Sep 2021, 10:16
2
sandy wrote:
a ≠ –b
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{6a^2+12ab+6b^2}{(a+b)}\) |
\(6(a+b)\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 5
Page: 511
Question: 5
Page: 511
Given:
QUANTITY A: \(\frac{6a^2+12ab+6b^2}{(a+b)}\)
QUANTITY B: \(6(a+b)\)
First factor out the 6 from numerator in Quantity A to get:
QUANTITY A: \(\frac{6(a^2+2ab+b^2)}{(a+b)}\)
QUANTITY B: \(6(a+b)\)
Now factor quadratic in Quantity A to get:
QUANTITY A: \(\frac{6(a+b)(a+b)}{(a+b)}\)
QUANTITY B: \(6(a+b)\)
The \((a+b)\) terms cancel out in the denominator and numerator in Quantity A to get:
QUANTITY A: \(6(a+b)\)
QUANTITY B: \(6(a+b)\)
Answer: C
