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For all numbers x,
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Updated on: 27 Dec 2018, 09:48
Updated on: 27 Dec 2018, 09:48
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Question Stats:
62% (01:13) correct
37% (01:12) wrong based on 77 sessions
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For all numbers x, \(\boxed {x}\) denotes the value of \(x^3\) rounded to the nearest multiple of ten.
Quantity A |
Quantity B |
\(\boxed{x+1}+ 1\) |
\(\boxed {x} + 1\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: For all numbers x,
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17 Mar 2019, 16:34
17 Mar 2019, 16:34
4
Expert Reply
This one's a little bit of an oddball. Clearly, quantity A is going to be larger for positive integers. For instance, if x = 2, then \(\boxed{2+1}\) = \(\boxed{3}\) = \(3^{3}\) = 27, and the closest multiple of 10 is 30. So quantity A = 30 + 1 = 31. When x = 2 in quantity B, though, we get \(\boxed{2}\) = \(2^{3}\) = 8, and the nearest multiple of 10 is 10. So quantity B = 10 + 1 = 11. Hence, quantity A is larger.
However, when x = 0.0001, then each quantity's boxed value will be rounded down to 0 as the nearest multiple of 10. In that case, the quantities are equal.
And when say, x = -2, following the math before, we'd end up with quantity A = -31 and quantity b = -11, making quantity B bigger.
Since we don't know which case is true, the answer is D.
However, when x = 0.0001, then each quantity's boxed value will be rounded down to 0 as the nearest multiple of 10. In that case, the quantities are equal.
And when say, x = -2, following the math before, we'd end up with quantity A = -31 and quantity b = -11, making quantity B bigger.
Since we don't know which case is true, the answer is D.
