GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the triangle
[#permalink]
19 Mar 2020, 11:21
19 Mar 2020, 11:21
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
81% (00:25) correct
18% (00:25) wrong based on 72 sessions
Hide Show timer Statistics
Attachment:
#greprepclub In the triangle.jpg [ 26.99 KiB | Viewed 2690 times ]
Quantity A |
Quantity B |
\(x\) |
\(5 \sqrt{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: In the triangle
[#permalink]
09 Apr 2020, 19:46
09 Apr 2020, 19:46
1
Carcass wrote:
Attachment:
#greprepclub In the triangle.jpg
Quantity A |
Quantity B |
\(x\) |
\(5 \sqrt{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
in the right angled \triangle
By Pythagoras theorem,
x = \(\sqrt{{10}^2 - {5}^2} = \sqrt{75} = 5\sqrt{3}\)
Re: In the triangle
[#permalink]
12 Apr 2020, 02:50
12 Apr 2020, 02:50
pranab223 wrote:
Carcass wrote:
Attachment:
#greprepclub In the triangle.jpg
Quantity A |
Quantity B |
\(x\) |
\(5 \sqrt{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
in the right angled \triangle
By Pythagoras theorem,
x = \(\sqrt{{10}^2 - {5}^2} = \sqrt{75} = 5\sqrt{3}\)
your wrong.. it should be 5 root 3.
