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4s+3t=27
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16 Aug 2021, 14:39
16 Aug 2021, 14:39
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\(4s+3t=27\)
\(t=2s-1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(t=2s-1\)
Quantity A |
Quantity B |
s |
t |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Retired Moderator
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Re: 4s+3t=27
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17 Aug 2021, 07:07
17 Aug 2021, 07:07
1
Carcass wrote:
\(4s+3t=27\)
\(t=2s-1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(t=2s-1\)
Quantity A |
Quantity B |
s |
t |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Since \(t=2s-1\), we can replace \(t\) with \(2s-1\) in the first equation to get: \(4s+3(2s-1)=27\)
Expand: \(4s+6s-3=27\)
Simplify: \(10s-3=27\)
Solve: : \(s=3\)
To find the corresponding value of \(t\), plug \(s=3\) into the equation \(t=2s-1\) to get: \(t=2s-1 = 2(3)-1 = 6-1 = 5\)
We have:
QUANTITY A: 3
QUANTITY B: 5
Answer: B
gmatclubot
Re: 4s+3t=27 [#permalink]
17 Aug 2021, 07:07
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