GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
y is greater equal 2
[#permalink]
16 Jan 2020, 10:18
16 Jan 2020, 10:18
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
69% (01:14) correct
30% (01:22) wrong based on 156 sessions
Hide Show timer Statistics
\(y \geq 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{y!}{5(y-2)!}\) |
\(\frac{(y+1)!}{3(y-1)!}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: y is greater equal 2
[#permalink]
16 Jan 2020, 12:35
16 Jan 2020, 12:35
2
We need to take values for this questions.
1. y = 2
Option A: \(\frac{y!}{5(y-2)!} = \frac{2!}{5 \times 0!} = \frac{2}{5} = 0.4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{3!}{3 \times 2!} = \frac{6}{6} = 1\)
Option A < Option B
2. y = 5
Option A: \(\frac{y!}{5(y-2)!} = \frac{5!}{5 \times 3!} = \frac{120}{30} = 4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{6!}{3 \times 4!} = \frac{720}{72} = 10\)
Option A < Option B
We can see that as we keep increasing the value of y, the gap between Option A and Option B will keep increasing and Option A will always be smaller than Option B.
OA, B
1. y = 2
Option A: \(\frac{y!}{5(y-2)!} = \frac{2!}{5 \times 0!} = \frac{2}{5} = 0.4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{3!}{3 \times 2!} = \frac{6}{6} = 1\)
Option A < Option B
2. y = 5
Option A: \(\frac{y!}{5(y-2)!} = \frac{5!}{5 \times 3!} = \frac{120}{30} = 4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{6!}{3 \times 4!} = \frac{720}{72} = 10\)
Option A < Option B
We can see that as we keep increasing the value of y, the gap between Option A and Option B will keep increasing and Option A will always be smaller than Option B.
OA, B
Carcass wrote:
\(y \geq 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{y!}{5(y-2)!}\) |
\(\frac{(y+1)!}{3(y-1)!}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: y is greater equal 2
[#permalink]
16 Jan 2020, 12:37
16 Jan 2020, 12:37
Carcass wrote:
\(y \geq 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{y!}{5(y-2)!}\) |
\(\frac{(y+1)!}{3(y-1)!}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
If I were to plug in 2, I believe A becomes undefined whereas B becomes 1. In this particular case, would B be considered bigger? I am not sure how to compare a number against an undefined
