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Suzy purchased three books from a shop. The average (arithmetic mean)
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12 Oct 2023, 03:24
12 Oct 2023, 03:24
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Question Stats:
89% (01:21) correct
10% (01:47) wrong based on 19 sessions
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Suzy purchased three books from a shop. The average (arithmetic mean) price of the books was $1.50, which was also the price of one of the books.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The median price of the three books |
$1.50 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Suzy purchased three books from a shop. The average (arithmetic mean)
[#permalink]
08 Dec 2023, 02:13
08 Dec 2023, 02:13
Expert Reply
Suzy purchased three books from a shop. The average (arithmetic mean)
[#permalink]
10 Dec 2023, 09:38
10 Dec 2023, 09:38
1
Let us assume that the price of the 3 books are x, y and 1.5 (all figures in $)
Now, the mean is (x+y+1.5)/3=1.5
so, x+y=3, lets assume x>1.5, then y<1.5
if y>1.5 then x<1.5
If x=y, then both have values of 1.5
Whatever the values of x or y, when arranged in ascending order the price of the 3rd book (1.5) will be the middle value hence the median is also 1.5
so, both values are equal hence option C
Now, the mean is (x+y+1.5)/3=1.5
so, x+y=3, lets assume x>1.5, then y<1.5
if y>1.5 then x<1.5
If x=y, then both have values of 1.5
Whatever the values of x or y, when arranged in ascending order the price of the 3rd book (1.5) will be the middle value hence the median is also 1.5
so, both values are equal hence option C
