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( x + 3)(x 2)^2(x23)(2x 4) = 0
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17 Apr 2023, 01:17
17 Apr 2023, 01:17
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46% (01:03) correct
53% (01:09) wrong based on 79 sessions
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\(( x + 3)(x – 2)^2(x^2–3)(2x – 4) = 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Quantity A |
Quantity B |
The number of integer values of x for which above equation is true |
3 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Re: ( x + 3)(x 2)^2(x23)(2x 4) = 0
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25 May 2023, 13:23
25 May 2023, 13:23
Expert Reply
OE
We have to compare
Quantity A: The number of integer values of x for which above equation is true
Quantity B: 3
If the product of numbers is 0; then, at least one of them has to be 0.
Therefore, either 𝑥 + 3 = 0 or 𝑥 − 2 = 0 or 𝑥
2 − 3 = 0 or 2𝑥 – 4 = 0
i.e. 𝑥 = −3 or 𝑥 = 2 or 𝑥^2 = 3 or 2𝑥 = 4
Since, we want to find the number of integer values of x from the above equations,
𝑥^2 = 3 is giving me 𝑥 = ±√3 which is not integer.
Also, 2𝑥 = 4 gives us 𝑥 = 2.
So, we can see that the integer values of 𝑥 are -3 and 2.
Hence, quantity B is greater.
Ans. (B)
We have to compare
Quantity A: The number of integer values of x for which above equation is true
Quantity B: 3
If the product of numbers is 0; then, at least one of them has to be 0.
Therefore, either 𝑥 + 3 = 0 or 𝑥 − 2 = 0 or 𝑥
2 − 3 = 0 or 2𝑥 – 4 = 0
i.e. 𝑥 = −3 or 𝑥 = 2 or 𝑥^2 = 3 or 2𝑥 = 4
Since, we want to find the number of integer values of x from the above equations,
𝑥^2 = 3 is giving me 𝑥 = ±√3 which is not integer.
Also, 2𝑥 = 4 gives us 𝑥 = 2.
So, we can see that the integer values of 𝑥 are -3 and 2.
Hence, quantity B is greater.
Ans. (B)
Re: ( x + 3)(x 2)^2(x23)(2x 4) = 0
[#permalink]
26 Sep 2024, 06:06
26 Sep 2024, 06:06
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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