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The line y=-8/7x is graphed on the rectangular coordinate axes.
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Updated on: 30 Mar 2024, 00:51
Updated on: 30 Mar 2024, 00:51
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71% (01:15) correct
28% (01:59) wrong based on 53 sessions
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The line \(y=-\frac{8}{7}x+1\) is graphed on the rectangular coordinate axes.
Quantity A |
Quantity B |
OR |
OP |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes.
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26 Jun 2023, 02:09
26 Jun 2023, 02:09
7
But the equation says y = -8/7*x right? in that case as y-intercept of line is 0, line will pass through origin. What am I not understanding?
General Discussion
The line y=-8/7x is graphed on the rectangular coordinate axes.
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05 Jun 2023, 04:00
05 Jun 2023, 04:00
2
Expert Reply
OE
The y-intercept, or b, in this case is 1. That means the line crosses the
y-axis at 1. So the coordinates of point P are (0, 1). Now we have to
determine the coordinates of point R. We know the y-coordinate is 0,
so let’s stick that into the equation (the slope and the y-intercept are
constant; they don’t change).
y = mx + b
\(0=-\frac{8}{7}x+1\)
Solving
\(x=\frac{7}{8}
\)
So the coordinates of point R are (7/8 , 0). That means OR, in Quantity A, is equal to , and OP, in Quantity B, is equal to 1. The answer is (B).
The y-intercept, or b, in this case is 1. That means the line crosses the
y-axis at 1. So the coordinates of point P are (0, 1). Now we have to
determine the coordinates of point R. We know the y-coordinate is 0,
so let’s stick that into the equation (the slope and the y-intercept are
constant; they don’t change).
y = mx + b
\(0=-\frac{8}{7}x+1\)
Solving
\(x=\frac{7}{8}
\)
So the coordinates of point R are (7/8 , 0). That means OR, in Quantity A, is equal to , and OP, in Quantity B, is equal to 1. The answer is (B).
