We have \(abc<0\) this means that either a, b , c or all three are negative. Since product of the three is negative.

Now \(b^2c>0\). Since \(b^2\) is always a positive number then \(c\) must be a positive number for \(b^2c>0\) to be true.

For \(abc<0\) to be true \(ab<0\) must be true, since c is a positive number.

Thus Quantity A, namely \(ab\), is less than Quantity B, which is 0.

\(b^2c > 0\)

\(b^2\) will be always positive which means \(c > 0\)

\(abc < 0\)

Since \(c > 0\), this naturally makes \(ab < 0\)

Hence, Answer is B

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