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9 friends contributed an integer amount between $15 and $24, inclusive
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27 Jul 2023, 06:37
27 Jul 2023, 06:37
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60% (01:20) correct
39% (01:28) wrong based on 33 sessions
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9 friends contributed an integer amount between $15 and $24, inclusive, in charity. The median amount given by 9 friends was $20
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Quantity A |
Quantity B |
The average amount contributed by 9 friends |
18 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE Math Essentials - A most comprehensive handout!!
\(\Longrightarrow\) Free Materials for the GRE General Exam - Where to get it!!
\(\Longrightarrow\) Best GRE Test Books of 2023
Re: 9 friends contributed an integer amount between $15 and $24, inclusive
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28 Jul 2023, 21:30
28 Jul 2023, 21:30
Can anyone explain this ? As i've got A as the answer
Re: 9 friends contributed an integer amount between $15 and $24, inclusive
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30 Jul 2023, 23:15
30 Jul 2023, 23:15
2
Expert Reply
OE
It is given that 9 friends contributed an integer amount between $15 and $24, inclusive, in charity.
The median amount given by them was $20.
We know median amount, i.e. we know 5th term is 20$. (When the terms are arranged in ascending order, central value is median.)
To calculate average, we need to know all the terms. We know the 5th i.e. central term only.
Consider following cases, Let the contributions are
Set 1: To find minimum possible value of mean, let’s keep all the values as minimum.
15$, 15$, 15$, 15$, 20$, 20$, 20$, 20$, 20$
For this set, mean is 17.77.
Set 2: To find maximum possible value of mean, let’s keep all the values as maximum.
$20, $20, $20, $20, $20, $24, $24, $24, $24
For this set, mean is 21.77.
So, Quantity A could be greater, equal or smaller than Quantity B.
Hence, we cannot compare both quantities.
Ans. (D)
It is given that 9 friends contributed an integer amount between $15 and $24, inclusive, in charity.
The median amount given by them was $20.
We know median amount, i.e. we know 5th term is 20$. (When the terms are arranged in ascending order, central value is median.)
To calculate average, we need to know all the terms. We know the 5th i.e. central term only.
Consider following cases, Let the contributions are
Set 1: To find minimum possible value of mean, let’s keep all the values as minimum.
15$, 15$, 15$, 15$, 20$, 20$, 20$, 20$, 20$
For this set, mean is 17.77.
Set 2: To find maximum possible value of mean, let’s keep all the values as maximum.
$20, $20, $20, $20, $20, $24, $24, $24, $24
For this set, mean is 21.77.
So, Quantity A could be greater, equal or smaller than Quantity B.
Hence, we cannot compare both quantities.
Ans. (D)
