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A bowl contains few mangoes and few oranges in the ratio 3 : 1. Anothe
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13 Nov 2023, 01:42
13 Nov 2023, 01:42
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A bowl contains few mangoes and few oranges in the ratio 3 : 1. Another bowl contains four fruits, two of which are mangoes and the rest are oranges. One of the fruits from the first bowl, selected at random, is replaced by one of the fruits from the second bowl, also selected at random.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Probability that the number of mangoes in the first bowl will increase |
\(\frac{1}{8}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: A bowl contains few mangoes and few oranges in the ratio 3 : 1. Anothe
[#permalink]
14 Nov 2023, 18:32
14 Nov 2023, 18:32
1
First bowl contains mangoes to orange in ratio - 3:1
Second bowl contains mangoes to orange in ratio - 1:1 ( 2 mangoes and 2 oranges )
Now the Probability that the number of mangoes in the first bowl will increase = probability that the orange is selected from the first bowl and to be placed in second bowl and the probability that the mango is selected from the second bowl and to be placed in first bowl
probability that the orange is selected from the first bowl to be placed in second bowl = 1/4 (since for every 1 orange the bowl contains 4 fruits)
probability that the mango is selected from the second bowl and to be placed in first bowl = 1/2 (since for every 1 mango , the bowl contains 2 fruits)
Thus total probability = 1/4 * 1/2 = 1/8 -- answer C
Second bowl contains mangoes to orange in ratio - 1:1 ( 2 mangoes and 2 oranges )
Now the Probability that the number of mangoes in the first bowl will increase = probability that the orange is selected from the first bowl and to be placed in second bowl and the probability that the mango is selected from the second bowl and to be placed in first bowl
probability that the orange is selected from the first bowl to be placed in second bowl = 1/4 (since for every 1 orange the bowl contains 4 fruits)
probability that the mango is selected from the second bowl and to be placed in first bowl = 1/2 (since for every 1 mango , the bowl contains 2 fruits)
Thus total probability = 1/4 * 1/2 = 1/8 -- answer C
gmatclubot
Re: A bowl contains few mangoes and few oranges in the ratio 3 : 1. Anothe [#permalink]
14 Nov 2023, 18:32
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