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x > 3^20
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22 Nov 2023, 03:05
22 Nov 2023, 03:05
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54% (01:50) correct
45% (01:22) wrong based on 11 sessions
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\(x > 3^{20}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(x\) |
\(6^{12}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
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x > 3^20
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01 Dec 2023, 20:03
01 Dec 2023, 20:03
1
Not 100% confident that this is the best approach, so correct me if there's a better way but:
I'd compare \(3^{20}\) to \(6^{12}\).
\(6^{12} = (3*2)^{12} = 3^{12}*2^{12}\)
Simplify to then compare \(3^8\) to \(2^{12}\).
This is where I'd brute-force calculate to get \(3^8=6561\) and \(2^{12}=4096\).
Now we know that \(3^{20}>6^{12}\) and \(x > 3^{20}\), x must be greater than \(6^{12}\).
I'd compare \(3^{20}\) to \(6^{12}\).
\(6^{12} = (3*2)^{12} = 3^{12}*2^{12}\)
Simplify to then compare \(3^8\) to \(2^{12}\).
This is where I'd brute-force calculate to get \(3^8=6561\) and \(2^{12}=4096\).
Now we know that \(3^{20}>6^{12}\) and \(x > 3^{20}\), x must be greater than \(6^{12}\).
Re: x > 3^20
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08 Jan 2024, 02:23
08 Jan 2024, 02:23
Carcass can you guide me? not able to figure out less time consuming way to solve this question
