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(a 2)^2 + |b 2| = 0
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07 Dec 2023, 01:04
07 Dec 2023, 01:04
1
Expert Reply
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Question Stats:
71% (01:15) correct
28% (02:13) wrong based on 14 sessions
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\((a − 2)^2 + |b − 2| = 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{a}{b}\) |
2 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: (a 2)^2 + |b 2| = 0
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08 Dec 2023, 15:46
08 Dec 2023, 15:46
Expert Reply
Manager
Joined: 11 Nov 2023
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(a 2)^2 + |b 2| = 0
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11 Dec 2023, 01:22
11 Dec 2023, 01:22
2
Since the square of a value and absolute value will always be equal to or greater than 0, and the full equation = 0, both \((a-2)^2\) and \(|b-2|\) must equal 0.
When \((a-2)^2 = 0\), the only value for a is 2.
When \(|b-2| = 0\), the only value for b is 2.
\(\frac{a}{b} = \frac{2}{2} =1\), so B is greater than A.
When \((a-2)^2 = 0\), the only value for a is 2.
When \(|b-2| = 0\), the only value for b is 2.
\(\frac{a}{b} = \frac{2}{2} =1\), so B is greater than A.
