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In the triangle shown above, a^2 + b^2 < 15 and c = 4
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12 Dec 2023, 05:27
12 Dec 2023, 05:27
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In the triangle shown above, \(a^2 + b^2 < 15\) and c = 4
Quantity A |
Quantity B |
\(x°\) |
\(90° \) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: In the triangle shown above, a^2 + b^2 < 15 and c = 4
[#permalink]
12 Dec 2023, 09:51
12 Dec 2023, 09:51
1
The answer is A.
If x = 90°, then a^2 + b^2 = c^2
If x > 90°, then a^2 + b^2 < c^2
If x < 90°, then a^2 + b^2 > c^2
We know that a^2 + b^2 < 15
& since c = 4 --> c^2 = 16
Hence, a^2 + b^2 < c^2
Therefore, x > 90°
If x = 90°, then a^2 + b^2 = c^2
If x > 90°, then a^2 + b^2 < c^2
If x < 90°, then a^2 + b^2 > c^2
We know that a^2 + b^2 < 15
& since c = 4 --> c^2 = 16
Hence, a^2 + b^2 < c^2
Therefore, x > 90°
gmatclubot
Re: In the triangle shown above, a^2 + b^2 < 15 and c = 4 [#permalink]
12 Dec 2023, 09:51
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