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The nets for a cube and a cuboid
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17 Jan 2024, 01:57
17 Jan 2024, 01:57
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Thе nеts fоr а cubе аnd а cubоid аrе shоwn with thеir dimеnsiоns. Thеy аrе nоt drаwn tо scаlе.
GRE geometry practice question.jpg [ 50.99 KiB | Viewed 555 times ]
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Attachment:
GRE geometry practice question.jpg [ 50.99 KiB | Viewed 555 times ]
Quantity A |
Quantity B |
Thе surfаcе аrеа оf thе cubе. |
Thе surfаcе аrеа оf thе cubоid. |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Re: The nets for a cube and a cuboid
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17 Jan 2024, 23:07
17 Jan 2024, 23:07
1
The surface area of a cube where x = length of a side is \(6x^2\),
so Quantity A = \(6 * 4^2 = 96\)
The surface area of a cuboid with dimensions a, b, and c is \(2(ab + ac + bc)\),
so Quantity B = \(2(6*2 + 3*2 + 6*3) = 2(12+6+18) = 2(36) = 72\)
Since 96 > 72, Quantity A > Quantity B.
so Quantity A = \(6 * 4^2 = 96\)
The surface area of a cuboid with dimensions a, b, and c is \(2(ab + ac + bc)\),
so Quantity B = \(2(6*2 + 3*2 + 6*3) = 2(12+6+18) = 2(36) = 72\)
Since 96 > 72, Quantity A > Quantity B.
gmatclubot
Re: The nets for a cube and a cuboid [#permalink]
17 Jan 2024, 23:07
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