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4x^2-17x+4=0
[#permalink]
29 Feb 2024, 05:05
29 Feb 2024, 05:05
Expert Reply
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Question Stats:
77% (01:10) correct
22% (00:46) wrong based on 9 sessions
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\(4x^2-17x+4=0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(x\) |
[\(\sqrt{\frac{1}{16}}\)] |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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4x^2-17x+4=0
[#permalink]
29 Feb 2024, 09:52
29 Feb 2024, 09:52
1
Quantity A
Factor the quadratic equation to find x:
\(4x^2−17x+4 = 0\)
\((4x-1)(x-1) = 0\)
\(x = 4\) or \(\frac{1}{4}\)
Quantity B
\(\sqrt{\frac{1}{16}} = -\frac{1}{4}\) or \(\frac{1}{4}\)
If x = 4, then Quantity A will be greater than Quantity B.
If x = 1/4 and Quantity B is 1/4, then the quantities are equal.
Therefore, the relationship cannot be determined.
Factor the quadratic equation to find x:
\(4x^2−17x+4 = 0\)
\((4x-1)(x-1) = 0\)
\(x = 4\) or \(\frac{1}{4}\)
Quantity B
\(\sqrt{\frac{1}{16}} = -\frac{1}{4}\) or \(\frac{1}{4}\)
If x = 4, then Quantity A will be greater than Quantity B.
If x = 1/4 and Quantity B is 1/4, then the quantities are equal.
Therefore, the relationship cannot be determined.
gmatclubot
4x^2-17x+4=0 [#permalink]
29 Feb 2024, 09:52
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