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In the series of all consecutive integers from 1 to n inclusive, the
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12 Aug 2024, 02:21
12 Aug 2024, 02:21
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Question Stats:
90% (01:03) correct
9% (01:49) wrong based on 11 sessions
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In the series of all consecutive integers from 1 to n inclusive, the product of all the numbers in the series is divisible by 990.
Quantity A |
Quantity B |
n |
9 |
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
Re: In the series of all consecutive integers from 1 to n inclusive, the
[#permalink]
20 Sep 2024, 03:27
20 Sep 2024, 03:27
990 = 2*3^2*5*11, because 11 is a prime number, the series of all consecutive integers from 1 to n must include 11, then n > 9
=> A
=> A
gmatclubot
Re: In the series of all consecutive integers from 1 to n inclusive, the [#permalink]
20 Sep 2024, 03:27
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