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1/0.001<(1/10)^n-4
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25 May 2020, 10:28
25 May 2020, 10:28
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50% (01:36) correct
50% (01:27) wrong based on 138 sessions
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\(\frac{1}{0.001}<(\frac{1}{10})^{n-4}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(|n-1|\) |
\( 1-n\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: 1/0.001<(1/10)^n-4
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25 May 2020, 10:28
25 May 2020, 10:28
1
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: 1/0.001<(1/10)^n-4
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26 May 2020, 15:14
26 May 2020, 15:14
1
we are given,
1/0.001 < (1/10)^(n-4) , this can be written as
10^3 < (10^-1)^(n-4) , upon further simplification
10^3 < (10) ^(4-n) , applying inequality to the exponents , we get
3< 4 - n , subtracting both side by 4
-1< -n , multiplying both sides by -1 and flipping the inequality, we get
1> n
take different values of n ,
case 1)
n = 0.99
A = I n-1I = I 0.99 - 1 I = I - 0.01I = 0.01
B = 1-n = 1 - 0.99 = 0.01
thus A = B for case 1
case 2 )
n= 0
A = I n - 1 I = I -1 I = 1
B= 1-n = 1
for this case also A=B
now take an extreme case like n = -1000
case 3 ) n = -1000
A= I n-1 I = I -1000 - 1 I = I -1001 I = 1001
B = 1- n = 1 - (-1000) = 1 + 1000 = 1001
thus for this case too A = B
hence we can conclude that A = B ( option c)
1/0.001 < (1/10)^(n-4) , this can be written as
10^3 < (10^-1)^(n-4) , upon further simplification
10^3 < (10) ^(4-n) , applying inequality to the exponents , we get
3< 4 - n , subtracting both side by 4
-1< -n , multiplying both sides by -1 and flipping the inequality, we get
1> n
take different values of n ,
case 1)
n = 0.99
A = I n-1I = I 0.99 - 1 I = I - 0.01I = 0.01
B = 1-n = 1 - 0.99 = 0.01
thus A = B for case 1
case 2 )
n= 0
A = I n - 1 I = I -1 I = 1
B= 1-n = 1
for this case also A=B
now take an extreme case like n = -1000
case 3 ) n = -1000
A= I n-1 I = I -1000 - 1 I = I -1001 I = 1001
B = 1- n = 1 - (-1000) = 1 + 1000 = 1001
thus for this case too A = B
hence we can conclude that A = B ( option c)
