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The price of a vanilla candy is $x less than twice the cost of a choco
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17 Apr 2023, 01:20
17 Apr 2023, 01:20
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The price of a vanilla candy is $x less than twice the cost of a chocolate candy. Their combined cost is less than the cost of 3 vanilla candies.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
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\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Quantity A |
Quantity B |
Cost of 4 chocolate candies |
8/3 x |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Re: The price of a vanilla candy is $x less than twice the cost of a choco
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17 Apr 2023, 07:24
17 Apr 2023, 07:24
4
A bit laborious, but it gives the answer.
VC = Vanilla Candy
CC = Chocolate Candy
The price of a vanilla candy is $x less than twice the cost of a chocolate candy.
VC = 2CC - X --- (1)
Their combined cost is less than the cost of 3 vanilla candies.
VC + CC < 3VC --- (2)
substituting (1) in (2)
2CC - X + CC < 3VC
3CC - X < 3VC
3CC - 3VC < X
3CC - 3(2CC - X) < X
3CC - 6CC + 3X < X
-3CC + 3X < X
-3CC < X - 3X
-3CC < -2X
multiplying throughout by - 1
3CC > 2X
Since Quantity B is (8/3)X, we divide throughout by 3/4 to get
3CC/(3/4) > 2X/(3/4)
4CC > 8/3X
Quantity A is greater than Quantity B
Choice A
VC = Vanilla Candy
CC = Chocolate Candy
The price of a vanilla candy is $x less than twice the cost of a chocolate candy.
VC = 2CC - X --- (1)
Their combined cost is less than the cost of 3 vanilla candies.
VC + CC < 3VC --- (2)
substituting (1) in (2)
2CC - X + CC < 3VC
3CC - X < 3VC
3CC - 3VC < X
3CC - 3(2CC - X) < X
3CC - 6CC + 3X < X
-3CC + 3X < X
-3CC < X - 3X
-3CC < -2X
multiplying throughout by - 1
3CC > 2X
Since Quantity B is (8/3)X, we divide throughout by 3/4 to get
3CC/(3/4) > 2X/(3/4)
4CC > 8/3X
Quantity A is greater than Quantity B
Choice A
Re: The price of a vanilla candy is $x less than twice the cost of a choco
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11 Nov 2024, 23:54
11 Nov 2024, 23:54
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
