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|-x|>=6
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17 Jul 2020, 06:44
17 Jul 2020, 06:44
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Question Stats:
74% (01:06) correct
25% (01:19) wrong based on 62 sessions
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|-x|>=6
\(xy^2<0\) where y is an integer.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(xy^2<0\) where y is an integer.
Quantity A |
Quantity B |
x |
-4 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: |-x|>=6
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17 Jul 2020, 06:47
17 Jul 2020, 06:47
My question:
For the 1st inequality, don't we remove the negative sign from the beginning because of the presence of the absolute value?
so we solve it,
|x|>=6
then
x>=6
x=<-6
and the we continue?
For the 1st inequality, don't we remove the negative sign from the beginning because of the presence of the absolute value?
so we solve it,
|x|>=6
then
x>=6
x=<-6
and the we continue?
Re: |-x|>=6
[#permalink]
17 Jul 2020, 10:21
17 Jul 2020, 10:21
1
1
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Asmakan wrote:
My question:
For the 1st inequality, don't we remove the negative sign from the beginning because of the presence of the absolute value?
so we solve it,
|x|>=6
then
x>=6
x=<-6
and the we continue?
For the 1st inequality, don't we remove the negative sign from the beginning because of the presence of the absolute value?
so we solve it,
|x|>=6
then
x>=6
x=<-6
and the we continue?
|x|>=6 and |-x|>=6 both imply the same that either x>=6 or x<=-6. So it doesn't matter.
since, xy^2 < 0
=> x < 0 (since y^2 > 0)
=> x <= -6 (since |-x|>=6)
=> x < -4
So, the answer is B
