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The average salary of one group having n number of employees is $32,00
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30 Sep 2024, 00:40
30 Sep 2024, 00:40
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Question Stats:
62% (02:02) correct
37% (03:17) wrong based on 8 sessions
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The average salary of one group having n number of employees is $32,000 and the average salary of another group having (n–1) number of employees is $33,000.
Quantity A |
Quantity B |
The average salary of all the \((2n–1)\) employees |
$32,500 |
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Re: The average salary of one group having n number of employees is $32,00
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10 Oct 2024, 05:51
10 Oct 2024, 05:51
Can someone please explain how B is the answer?
Re: The average salary of one group having n number of employees is $32,00
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10 Oct 2024, 08:49
10 Oct 2024, 08:49
Expert Reply
The average salary of the combined group is
\(n+(n-1)=2n+1\)
Now
\(\frac{32000*n+33000(n-1)}{n+(n-1)}\)
This average is more close to 32000 than 3000
The salary , in a nutshell, would be >32000 but < 32500
So B is the answer
PS: this is the concept of the weighted avergae
\(n+(n-1)=2n+1\)
Now
\(\frac{32000*n+33000(n-1)}{n+(n-1)}\)
This average is more close to 32000 than 3000
The salary , in a nutshell, would be >32000 but < 32500
So B is the answer
PS: this is the concept of the weighted avergae
