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$$ \begin{gathered} S=\{1,2,3,4,6,8\} \\ T=\{1,2,3,6,8\} \end{gathered
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10 Mar 2025, 23:15
10 Mar 2025, 23:15
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Question Stats:
28% (01:29) correct
71% (01:16) wrong based on 7 sessions
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$$
\(\begin{gathered}
S=\{1,2,3,4,6,8\} \\
T=\{1,2,3,6,8\}
\end{gathered}\)
$$
$\(a\)$ is a number in set $S$, and $b$ is a number in set $\(T\)$
\(\begin{gathered}
S=\{1,2,3,4,6,8\} \\
T=\{1,2,3,6,8\}
\end{gathered}\)
$$
$\(a\)$ is a number in set $S$, and $b$ is a number in set $\(T\)$
Quantity A |
Quantity B |
The number of different values of the product $\(a b\)$ |
30 |
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Re: $$ \begin{gathered} S=\{1,2,3,4,6,8\} \\ T=\{1,2,3,6,8\} \end{gathered
[#permalink]
12 Mar 2025, 03:09
12 Mar 2025, 03:09
2
Lets save some time
immediately by looking at the problem it should be evident that option B is correct since both sets have some numbers that are same which results
in some products being same
total number of products possible = 6*5 = 30
and therefore quantity A should obviously be less than quantity B
heres a detailed explanation
lets pluck out same product values
1*2 and 2*1 (-1)
1*3 and 3*1(-1)
1*6 and 6*1 (-1)
1*8 and 8*1 (-1)
= -4
2*3 and 3*2 (-1)
2*2 and 4*1 (-1)
2*6 and 6*2 (-1)
2*8 and 8*2(-1)
= -4
3*6 and 6*3 (-1)
3*8 and 8*3 (-1)
= -2
6*8 and 8*6 (-1)
= -1
total = -11
so number of distinctive solutions is 30-11 = 19
option B should be right
kudos is appreciated
immediately by looking at the problem it should be evident that option B is correct since both sets have some numbers that are same which results
in some products being same
total number of products possible = 6*5 = 30
and therefore quantity A should obviously be less than quantity B
heres a detailed explanation
lets pluck out same product values
1*2 and 2*1 (-1)
1*3 and 3*1(-1)
1*6 and 6*1 (-1)
1*8 and 8*1 (-1)
= -4
2*3 and 3*2 (-1)
2*2 and 4*1 (-1)
2*6 and 6*2 (-1)
2*8 and 8*2(-1)
= -4
3*6 and 6*3 (-1)
3*8 and 8*3 (-1)
= -2
6*8 and 8*6 (-1)
= -1
total = -11
so number of distinctive solutions is 30-11 = 19
option B should be right
kudos is appreciated
gmatclubot
Re: $$ \begin{gathered} S=\{1,2,3,4,6,8\} \\ T=\{1,2,3,6,8\} \end{gathered [#permalink]
12 Mar 2025, 03:09
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