Column A: $\(6!=2 \times 3 \times 4 \times 5 \times 6=2^4 \times 3^2 \times 5\)$.

Therefore, the total number of factors of $\(6!=(4+1)(2+1)(1+1)=5 \times 3 \times 2=30\)$. Column B: $\(735=5 \times 147=5 \times 7 \times 21=5 \times 7^2 \times 3\)$.

Therefore, the total number of factors of $7\(35=(2+1)(1+1)(1+1)=3 \times 2 \times 2=12\)$. Hence, Column $\(\mathrm{A}>\)$ Column B. Thus, the correct answer is $\(A\)$.