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(n 2) (n 3) = 0
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17 Mar 2025, 01:08
17 Mar 2025, 01:08
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Question Stats:
63% (00:49) correct
36% (01:04) wrong based on 11 sessions
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\( (n – 2) (n – 3) = 0\)
Quantity A |
Quantity B |
\(-2n-1\) |
\(2n+1\) |
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(n 2) (n 3) = 0
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17 Mar 2025, 07:32
17 Mar 2025, 07:32
1
Given that (n-2)(n-3)=0, the solutions to the equation are n = 2 or 3.
When n = 2:
Quantity A = −2(2)−1 = -5
Quantity B = 2(2)+1 = 5
Since 5>-5, Quantity B is greater
When n = 3:
Quantity A = −2(3)−1 = -7
Quantity B = 2(3)+1 = 7
Since 7>-7, Quantity B is greater
Quantity B is greater for both solutions of n, so the answer is B.
When n = 2:
Quantity A = −2(2)−1 = -5
Quantity B = 2(2)+1 = 5
Since 5>-5, Quantity B is greater
When n = 3:
Quantity A = −2(3)−1 = -7
Quantity B = 2(3)+1 = 7
Since 7>-7, Quantity B is greater
Quantity B is greater for both solutions of n, so the answer is B.
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Re: (n 2) (n 3) = 0
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26 Jul 2025, 01:31
26 Jul 2025, 01:31
1
\( (n – 2) (n – 3) = 0\)
=> n = 2 or 3
Quantity A
-2n - 1 = -(2n + 1) = -(Quantity B)
Since, n is positive so Quantity B which is positive will always be greater than Quantity A which is negative!
So, Answer will be B
Hope it helps!
Playlist on Solved Problems on Sequences here
Calculation for both the values of n below
Quantity A
For n = 2, -2n-1 = -2*2 - 1 = -5
For n = 3, -2n - 1 = -2*3 - 1 = -7
Quantity B = 5 and 7 respectively
=> n = 2 or 3
Quantity A
-2n - 1 = -(2n + 1) = -(Quantity B)
Since, n is positive so Quantity B which is positive will always be greater than Quantity A which is negative!
So, Answer will be B
Hope it helps!
Playlist on Solved Problems on Sequences here
Calculation for both the values of n below
Quantity A
For n = 2, -2n-1 = -2*2 - 1 = -5
For n = 3, -2n - 1 = -2*3 - 1 = -7
Quantity B = 5 and 7 respectively
