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GRE Math Challenge #33- x^2-3x+2=0
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Updated on: 18 Feb 2020, 10:00
Updated on: 18 Feb 2020, 10:00
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Question Stats:
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25% (00:32) wrong based on 111 sessions
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\(x^2-3x+2=0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Twice the sum of the roots of the equation |
6 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: GRE Math Challenge #33
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13 Apr 2015, 06:10
13 Apr 2015, 06:10
1
sandy wrote:
-------------------------------------
x² - 3x + 2 = 0
Column A: Twice the sum of the roots of the equation
Column B: 6
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
x² - 3x + 2 = 0
Column A: Twice the sum of the roots of the equation
Column B: 6
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
--------------------------------------
x² - 3x + 2 = 0
Factor to get: (x - 1)(x - 2) = 0
So, x = 1 or x = 2
Column A: Twice the sum of the roots of the equation
Sum of roots = 1 + 2 = 3
So, TWICE the sum = (2)(3) = 6
Column B: 6
Answer:
Show: ::
C
Cheers,
Brent
Re: GRE Math Challenge #33- x^2-3x+2=0
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11 Mar 2018, 06:30
11 Mar 2018, 06:30
sandy wrote:
\(x^2-3x+2=0\)
Column A: Twice the sum of the roots of the equation
Column B: 6
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Column A: Twice the sum of the roots of the equation
Column B: 6
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Let's do the factorization of \(x^2-3x+2=0\) which is (x-1)(x-2).
The roots of equation is 1 and 2 whose sum is 3.
For Qaunt A, Twice the sum of the roots of the equation would be 6.
then A=B
ANS C
