how do you know both are square and have length of 6.
is there something i need to know because i'm solving questions from question bank by selecting difficult.
are some questions grouped together or what cuz on some questions i'm not getting enough info to solve them but in the solution below you're quoting the specifics

You have two squares

In QB 36 is the hint because is the area

Can be solved also this way

- The right rectangle $B E F C$ is shaded and appears to be a square of side 8 , so its area is $\(8^2=64\)$.


- The left rectangle $A B E D$ has the same height 8 and width 6 , so its area is $\(6 \times 8=48\)$.


- Inside $\(A B E D\)$, a diagonal from $A$ to $E$ splits it into two congruent right triangles; only the upper one is shaded, so the shaded area there is $\(\frac{1}{2} \times 48=24\)$.


- Total shaded area $\(=64+24=88\)$, while Quantity B is $\(36+16=52\)$; hence Quantity A is greater.