Given:
- $O$ is the center of the circle.
- $\(\angle Q O R>\angle P O S\)$.

Key point:
In a circle, the measure of an arc is equal to the measure of the central angle that subtends the arc.

So, the minor arc measure is equal to the measure of the central angle.
Since $\(\angle Q O R>\angle P O S\)$, the minor $\(\operatorname{arc} Q R\)$ is greater than the minor arc $\(P S\)$.

Conclusion:
Quantity A (minor arc $\(Q R\)$ ) is greater than Quantity B (minor arc $\(P S\)$ ).