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The remainder when 2^{37} is divided by 7
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03 Aug 2026, 09:01
03 Aug 2026, 09:01
Expert Reply
00:00
Question Stats:
33% (00:49) correct
66% (01:12) wrong based on 6 sessions
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Quantity A |
Quantity B |
The remainder when \(2^{37}\) is divided by 7 |
The remainder when \(6^{41}\) is divided by 7 |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
- Part of the project: GRE Daily Quant Challenge ALL 4 CORE QUANT AREAS
- Also replying to the unanswered questions
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2932
Given Kudos: 1260
GPA: 3.39
Re: The remainder when 2^{37} is divided by 7
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06 Aug 2026, 12:20
06 Aug 2026, 12:20
1
Expert Reply
Explanation
For Quantity A:
The powers of 2 repeat every 3:
2,4,1,2,4,1,...
So the remainder is 2.
For Quantity B:
The remainder is 6.
Since 6>2, Quantity B is greater.
Answer: B.
For Quantity A:
The powers of 2 repeat every 3:
2,4,1,2,4,1,...
So the remainder is 2.
For Quantity B:
The remainder is 6.
Since 6>2, Quantity B is greater.
Answer: B.
gmatclubot
Re: The remainder when 2^{37} is divided by 7 [#permalink]
06 Aug 2026, 12:20
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