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In a garden, there are only red, yellow, and blue flowers.
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19 Jun 2017, 11:49
19 Jun 2017, 11:49
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Question Stats:
77% (01:42) correct
22% (01:22) wrong based on 224 sessions
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In a garden, there are only red, yellow, and blue flowers. One–third of the flowers are red, and 40 percent are blue. One flower is chosen at random.
Quantity A |
Quantity B |
The probability that the flower chosen is not red |
The probability the flower chosen is not yellow |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: In a garden, there are only red, yellow, and blue flowers.
[#permalink]
16 Sep 2017, 23:42
16 Sep 2017, 23:42
4
The probability that the chosen flower is not red is equal to 1-1/3 = 0.67, i.e. the probability of choosing whatever flower minus the probability of choosing a red flower. The probability that the chosen flower is not yellow is equal to the sum of the probability of the flower being red or blue, i.e. 1/3 + 0.4 = 0.73. Thus the answer is B!
Re: In a garden, there are only red, yellow, and blue flowers.
[#permalink]
22 Sep 2017, 21:56
22 Sep 2017, 21:56
2
Carcass wrote:
In a garden, there are only red, yellow, and blue flowers. One–third of the flowers are red, and 40 percent are blue. One flower is chosen at random.
Quantity A |
Quantity B |
The probability that the flower chosen is not red |
The probability the flower chosen is not yellow |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Let take total number of flowers be 90 (Since it is divisible by 3 and 40% x 90 gives an integer , however the total number can be of any value as long as itis divisible by 3 and multiply with 40% gives an integer)
\(\frac{1}{3}\)*90 = 30 Red flowers
and 40% = 90*.4 = 36 blue flowers.
Therefore we have 24 yellow flowers (since 90 - (30+36))
Now The probability that the
flower chosen is not red = \(\frac{60}{90}\)(Since yellow =24 and Blue = 36 ie 24+46 =60)
And The probability the flower chosen is not yellow = \(\frac{66}{90}\)(Since Red =30and Blue = 36 ie 24+36 =66)
Therefore \(\frac{60}{90}\) < \(\frac{66}{90}\)
