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a = 5b^2 – 10b + 7
[#permalink]
21 Jun 2017, 13:08
21 Jun 2017, 13:08
2
1
Expert Reply
10
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Question Stats:
65% (01:28) correct
34% (01:34) wrong based on 385 sessions
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a = \(5b^2\) – 10b + 7
Quantity A |
Quantity B |
a |
b |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: a = 5b^2 – 10b + 7
[#permalink]
01 Mar 2018, 05:25
01 Mar 2018, 05:25
12
1
Bookmarks
It's a good question.
First need to simplify and then plugin as below:
Quantity A: \(5b^2\) – 10b + 7
Quantity B: b
So, we can add 10b on both Quantities, because the inequality will not change i.e:
Quantity A: \(5b^2\) + 7
Quantity B: 11b
Now, don't plugin -ve values, because Quantity A will always greater (being positive). Also in 0, Quantity A will be greater.
Finally, just check for positive values. You will see Again, Quantity A always greater.
For positive values, just plugin one value from (0 - 1) and other one from any value greater than 1.
Choice Choice A is correct.
First need to simplify and then plugin as below:
Quantity A: \(5b^2\) – 10b + 7
Quantity B: b
So, we can add 10b on both Quantities, because the inequality will not change i.e:
Quantity A: \(5b^2\) + 7
Quantity B: 11b
Now, don't plugin -ve values, because Quantity A will always greater (being positive). Also in 0, Quantity A will be greater.
Finally, just check for positive values. You will see Again, Quantity A always greater.
For positive values, just plugin one value from (0 - 1) and other one from any value greater than 1.
Choice Choice A is correct.
General Discussion
Re: a = 5b^2 – 10b + 7
[#permalink]
04 Feb 2018, 01:19
04 Feb 2018, 01:19
5
a = 5b^2 – 10b + 7
let b=0, so a=7
b=1, a= 2
b=-1, a=22
So Q.A is greater.
let b=0, so a=7
b=1, a= 2
b=-1, a=22
So Q.A is greater.
