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GRE Math Challenge #108- 2x + 3y = 29 and 3x + 4y = 41
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Updated on: 20 Feb 2020, 11:17
Updated on: 20 Feb 2020, 11:17
1
Expert Reply
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Question Stats:
79% (00:44) correct
20% (01:20) wrong based on 127 sessions
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\(2x + 3y = 29\)
\(3x + 4y = 41\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\(3x + 4y = 41\)
Quantity A |
Quantity B |
\(x +y\) |
12 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: GRE Math Challenge #108
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11 May 2015, 07:35
11 May 2015, 07:35
3
sandy wrote:
\(2x + 3y = 29\)
\(3x + 4y = 41\)
Quantity A: \(x +y\)
Quantity B: 12
\(3x + 4y = 41\)
Quantity A: \(x +y\)
Quantity B: 12
Nice question.
This one is a classic, because many students feel they need to solve the linear system for x and for y.
HOWEVER, the question doesn't require us to find the individual values of x and y.
All we need to do is find the value of x + y (quantity A)
We have 2x + 3y = 29 AND 3x + 4y = 41
Subtract the first equation from the second question to get:
(3x + 4y) - (2x + 3y) = 41 - 29
Simplify to get x + y = 12
Answer:
Show: ::
C
Cheers,
Brent
Re: GRE Math Challenge #108- 2x + 3y = 29 and 3x + 4y = 41
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20 Feb 2020, 11:18
20 Feb 2020, 11:18
Expert Reply
Bump for further discussion
